Dear Vivek,

this question has no simple answer because the scattering power of a droplet depends on a) scatter direction and b) on x-ray attenuation versus diameter (or radius) of the droplet.

For some simple cases the answer is easily achieved:

case a:

The droplet is sufficiently transparent to x-rays which are involved in the scatter process:

     1/µ >> r ; r= radius and µ= linear attenuation coefficient of the x-rays 

for the case of forward scatter (phis ~ 0°) and for the case of back scatter (phis ~ 180°) and all scatter angles inbetween all atoms of the droplet contribute to the total scatter Is in a similar way. Thus in this case a) the scatter strength is proportional to the volume of the droplet:

   Is ~ r3.

case b:

The droplet is sufficiently opaque to x-rays which are involved in the scatter process:

1/µ

 Thank You Sir, For your Valuable answer.