Please check problem 5-11.Here they have calculated the dislocation density as 1/l^2.I know that there is an alternative way to calculate the number of dislocations by considering a test area and counting the number of dislocations passing through the test area.However in this context I do not understand why should the numerator be 1 and not any other natural number wherein I can have any number of dislocations passing through the test area.Please explain me in an elaborate way.
These lines at the bottom of the image are hypothetical dislocations?
Grzegorz Cios Maybe I do not know.Do you know the answer to the question?
The unit of dislocation density (1/m^2) reflects a total length od dislocations in a unit volume of material, i.e (m/m^3 = 1/m^2). Best regards
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