suppose there are two material points, before deformation, they have coordinates (x) and (x+dx), the initial distance between these neighboring points are:
dS2=dx2
why do we need the distance to be square?
Igor Ravve
It is not the distance, it is the distance squared. The square is needed to convert the vector difference between the two positions, dx, into the scalar distance squared. If we take square root the, we will get the distance.
dx^2 is vector dx multiplied scalarly by itself and means dx1^2+dx2^2+dx3^2.
The distance ds = Sqrt [ dx1^2+dx2^2+dx3^2 ]
1 votes
1 thanks
Victor J. Аdlucky
Square of distance is more preferable because there exists simple tensorial (bilinear) relationship exactly between squares of lengths of initial and deformed linear elements.
0 votes
0 thanks
- Badges
- Science topic
- Similar topics
- Physical Sciences
- Mechanics
- Classical Mechanics
- Continuum Mechanics
More Jinhao Huang's questions See All
Similar questions and discussions