In my sample intensity decreases with increasing 2 theta angle? What may be the cause
Dear Sachin K. Yadav,
for the theta dependency of the XRD peak heights please see for example around page 22 of:
https://www.lkouniv.ac.in/site/writereaddata/siteContent/202005032229015914Balak-das-Crystal-Structure-Factor-calculation.pdf
Best regards
G.M.
absolutely agree with Gerhard Martens . It is Lorentz-polarization factor (LPF)(see pg 26 of the slide above) (1+cos^2 2\theta)/(sin^2 \theta * cos\theta) coming into play. We usually disregard very high 2\theta values in usual XRD , so we can see only the falling part of LPF. And for amorphous part of angle, greatest x-ray intensity would certainly be at no-deflection direction, and that would also fall with increasing angle of deflection (or diffraction, however you may place it)
It is because if we increase the angle, x-rays will get energy to propagate inside materials. So electrons that are present inside material could absorb energy and transmit and diffract less amount of energy because some energy gets absorbed by electrons. Because of this reason we get low intensity by increasing the angle.
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