thank you sir, James Garry , i have reading materials that said it depends on source if it is current or voltage , voltage source mean negative feedback .whereas positive feedback mean positive. but i didn't reached to conclusion why ?
As drawn, there is a constant voltage applied to the positive terminal of the op-amp. The current that flows through the resistor network, R3,R2,R1, leads to a voltage at the negative input. Imagine now if R1 is an open circuit, or a short - then two very different behaviours arise.
I can't quite see how changing the nature of the source (constant current or constant voltage) changes matters - maybe worth modelling in SPICE?
The voltage source has a very low output impedance Rin . The output is unpredictable . You have to measure the voltage sources in order to make a model ! It's an ordinary voltage negative feedback, wich can go to a Schmit triger .
Let say that AmpOP is not saturated and V° is the voltage at its inputs. Let say your source voltage is perfect, so Rin->0 . V°=Vin and
Vout =Vin(R1+R2)/R1 . It is a voltage negative feedback with gain >1 .