In "traditional" XRD using a Cu(Kalpha) source, the diffraction pattern gives the position of the diffraction peaks as a function of teta (or 2 teta), whereas when using synchrotron radiation the diffraction pattern gives the position of the diffraction peaks as a function of energy.
In both cases, the interplanar distance (d) is given by Bragg's law, as Dr. Martens explains; however, it must be adequately written:
For "traditional" XRD: 2*d*sin teta (variable)= lambda (fixed)
For synchrotron XRD: 2*d.sin teta (fixed) = lambda (variable)
as E(keV)= 12.4/lambda (Å), then
2*d.sin teta (fixed) = lambda (variable)= 12.4/E or
E*d*sin teta (fixed)=6.2 which is more frequently used.
As the value of "d" is the same in both equations, then:
lamba (fixed)/2*sin teta (variable) = 6.2/E*sin teta (fixed) or
E = 12.4* sin teta (variable) / lambda (fixed) * sin teta (fixed)
So you can transform the diffraction pattern from one technique to another.
P. Grima Gallardo Hi, Gallardo. so if i want to convert the synchrotron XRD data into conventional XRD (Cu K) data, what should i do? is there any suggestion? thank you.
It is very easy. You must adapt Bragg equation 2d sin(theta) = lambda for each experiment since for traditional XRD measurements lambda is fixed, whereas for synchrotron lambda is variable:
Traditional XRD: 2d sin (theta variable)=lambda (fixed) or 2d=lambda (fixed)/sin (teta variable)
Synchrotron: 2d sin (teta fixed) = lamda (variable) or 2d=lamda (variable)/sin (teta fixed). As the term 2d is identical for both expression, then:
sin (theta variable)= lambda fixed/lamda (variable)/sin (teta fixed)
Lambda fixed and sin (theta fixed) are parameters of the experiment whereas lambda variable is obtained from E (variable) using the expression E(keV)=12398/lambda(Å).
P. Grima Gallardo @ Sir, you are talking about synchrotron XRD data colleceted in energy dispersive mode. If we fix the wavelength, then we can collect XRD pattern with theta as variable (Bragg's law)
I use the method, our experiment parameter is E=15 keV, lamda (variable) =0.82656 (Å)
while I convert the data to Cu K (1.5418 Å ) have some problem
(1.5418 Å/0.82656 Å )=fixed
theta1 is the data from synchrotron
theta2 is the purpose Cu K data
sin(theta2) = fixed * sin(theta1)
while I implement operator in arcsin( fixed * sin(theta1)) to obtain the data, the fixed * sin(theta1) may upper than 1 that are not in arcsin() domain