SPARQL property paths only return the start and end nodes of a path and do not allow variables in property path expressions.
SPARQL property paths don't return intermediate nodes neither triples.
SPARQL property paths cannot retrieve and naturally represented a path in the tabular result format of SPARQL.
Considering RDF-Star and SPARQL-Star current specifications, is it possible to bind the RDF triples from a property path query to embedded triples of RDF-Star triples?
For example
SELECT ?since ?t WHERE { ns:p3 ns:FRIENDS_OF+ ns:p2 AS path (?s ?p ?o) ns:date_of_start ?since. BIND( AS ?t) FILTER (?since > 2016) . }
Similar to the Cypher query bellow
WITH 2016 AS since MATCH rels= (p1:Person) - [:FRIENDS_OF*1..2]->(p2:Person) WHERE ALL(k1 in relationships(rels) WHERE k1.date_of_start > since) RETURN rels;
RDF-star and SPARQL-star
Final Community Group Report 17 December 2021
https://w3c.github.io/rdf-star/cg-spec/2021-12-17.html
Hi,
Kindly refer this link:
https://graphdb.ontotext.com/documentation/standard/devhub/rdf-sparql-star.html
Best wishes..
You can't bind results of property paths to triples with standard SPARQL.
Pobably you could try something like this:
SELECT ?since ?t {
?f1 ns:FRIENDS_OF+ ?f2 .
ns:p3 ns:FRIENDS_OF* ?f1 .
?f2 ns:FRIENDS_OF* ns:p2 .
BIND(
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