Hi all,
I needed to prepare an alkaline SDS solution made of 1% SDS in 0.2 M NaOH. What I did is to dissolve 1 g of SDS in 100 ml of 0.2 M of NaOH.
Is it correct?
What does 1mg/ml of lysozyme in 50mM glucose, 10mM EDTA and 25 mM tris.Hcl mean? Does it mean that I take 1 mg of lysozyme and dissolve it in 1 ml of a solution containing all the other 3 components?
Thanks,
Silvia
For both of your solutions you should dissolve your solid in some of the solvent and dilute to a final volume i.e. 1% SDS: Dissolve and dilute 1g SDS to 100mL with 0.2M NaOH
https://books.google.co.nz/books?id=2DcyKqj6dDsC&pg=PA576&lpg=PA576&dq=hydrolysis+sodium+lauryl+sulfate+base&source=bl&ots=Dq8Fectm6j&sig=M5eR4Y9OYgT9gKYERNs7jY77ums&hl=en&sa=X&ved=0ahUKEwj0nMjWvqPNAhUFjpQKHS7rCtAQ6AEIIjAC#v=onepage&q=hydrolysis%20sodium%20lauryl%20sulfate%20base&f=false