I want only how he apply atomic and electronic cross-section, please
Dear Wedad A. Alwesabi ,
the relation of the x-ray attenuation cross section sigma with respect to the transmission T of a sample is given by:
T = I/Io = exp(-sigma*n*d)*) with n = the number density (i.e. the number of particles per unit volume of sample) of the attenuating particles**), and d the path length in the sample. This exponential equation is similar to the Lambert-Beer law.
However, in your case, I would like to suggest, to use the NIST/XCOM database***), which will directly deliver the energy dependence of the x-ray mass-attenuation coefficient (µ/rho) for the whole compound (here ZnO-TiO). You only have to acquire the mean density rhoZnO-TiO of the ZnO-TiO in your sample (i.e. the amount of ZnO-TiO per volume):
T = exp(-(µ/rho)ZnO-TiO * rhoZnO-TiO *d)
Both formulae are equivalent...
Please do not forget to consider the x-ray attenuation contribution of the host matrix of your sample...
*) see for example the section 'Attenuation of a beam of particles' in:
https://en.wikipedia.org/wiki/Cross_section_(physics)
and https://en.wikipedia.org/wiki/Absorption_cross_section
**) for example the compound 'ZnO-TiO' is here regarded as a particle being equivalent a 'molecule' TiZnO2. The attenuation cross section is calculated via your formula given in your attachment of your recent question:
https://www.researchgate.net/post/I_synthesized_TiO2-ZnO_nanocomposites_with_different_concentrations_My_question_about_molar_mass_of_this_composition
***) https://physics.nist.gov/PhysRefData/Xcom/html/xcom1.html
The calculation of the weighted sums of (µ/rho) for a compound, as it is presented in the attachment of **), is already done here...
Good luck and
best regards
G.M.
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