In orthogonal cutting operation, why thickness of chip after cut is greater than that of the before cut?
During cutting, the cutting edge of the tool is positioned a certain distance below the original work surface. This corresponds to the thickness of the chip prior to chip formation, to. As the chip is formed along the shear plane, its thickness increases to tc. The ratio of to to tc is called the chip thickness ratio (or simply the chip ratio) r. {r= to/tc}. The chip ratio is always less than one.
Why the chip thickness after cutting is always greater than the corresponding thickness before cutting?
most cases ,the chip is separated from work by the action of cutting tool ,under goes severe plastic deformation.This means the chip can not return to original dimension ,hence there shall always be strain associates with it.
so separated chip will have larger dimension than uncut chip thickness.
please refer metal cutting by M.Shaw for further.
The chip thickness increases as it slides at the shear plane
It becomes shorter such that the cut volume= the uncut volume
The width b emains unchanged. Then
loxto= lcxtc
The rate of removal vxtoxb=vfxtcxb
The chip ratio=to/tc = vf/v=
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