Let y = mx+b be a line such that the slope m is an irrational number. If this line is drawn on a grid, it nowhere passes through a point (x,y) such that both x and y are rational. What does it signify?
You specify that only the slope, m, is an irrational number. If I allow the y-intercept, b, to be a rational number, then the straight line can pass through the point (0,b) where both numbers are rational.