I want to form cellulose sponge using this method "Cellulose was
dissolved in 7% NaOH/12% urea/81% H2O solution at low temperature to obtain a 2 wt % solution. The cellulose solution was centrifuged at 5000 rpm for 10 min to remove some impurities. Subsequently, the desired amount of ECH the mixture was stirred in an ice bath for 1 h to yield a homogeneous solution, and then reacted at 65 C for 2 h. Finally, the resulting cellulose gels were immersed in deionized water to remove the residual reagents
Here in this i am not able to understand what is the amount of ECH is required forming the gel because gel is not form even after 12 hr in at 65 C.
I am adding 1 ml for 27 gm of cellulose solution .
generally ECH and Bisphenol is crosslink in 2:1 ratio for this i want to calculate -OH functional group in cellulose and its Molecular weight
Please, calculate amount of -OH group as 3 mol/mol cellulose and take cross-linking agent (CLA) for this amount. Pay attention, that the gel formation property is directly connected with a degree of cross-linking in cellulose derivative. Degree of cross-linking is resulted according to what amount of cross-linking agent, added to the polymer solution. If you use very little amount of CLA then your product will be watersoluble, if you use huge amount of it, you may have a product with a very small swelling capacity.
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