I am working on the antimcirobial activity of some biopolymeric films. I am using the serial dilution method for the same. I want to represent my data in the form of log CFU/g sample. Can anyone elaborate the procedure for the same?
Thank You in Anticipation.
If I understand your question
If you have 10000 cfu, the log10=4 ...... just like that
You divide the number of CFU detected for the sample by the gram mass of the sample. For example 1000 CFUs/0.2 grams of sample equals 5000CFU/g. If you have multiple samples, you average the CFU/g for each sample. If your sample is a liquid, you can use the density of the liquid to convert from volume to mass (ie. 1mL of a 1.01g/mL density converts to 1.01g per sample).
For example,
If the initial number is CFU /g 10000000 (log 7) and after the action of the potential antimicrobial agent, CFU / g is 12000 (log 4.08), the reduction log of CFU / g is 2.92 (almost 3 log units).
If you are simply immersing the films in a bacterial suspension, then after incubation comparing the viable count of the suspension, you just need to standardise and state the mass or volume of the antimicrobial polymer and then compare the cfu/mL of the suspension. If you are determining the bacterial survival on the polymers after attachment, then you need to state the surface area (perhaps as well as the volume if the antimicrobial is diffusible) because this is the factor that is operating. The result would be cfu/ mm2. If the antimicrobial is diffusible and the volume is important, then standardise the shape/size and use the surface area again.
- Badges
- Science topic
- Similar topics
- Biological Science
- Biota
- Eukaryota
- Fungi