I had prepared my ICP-AES sample by adding 10mg Nanoparticles in Conc. HNO3 and then diluting the sample to final 25 mL. Of the 25 mL of sample prepared 10 mL was sent for analysis. The result that I have received is 458.56 ppm
I want to know how how much of analyte species is present in 1mg of Nanoparticles ?
The sample you analyzed had 4 mg of Nanoparticle. Your analyte concentration was 458.56 mg/L (ppm). That means you had 0.45856 mg/ml. So now you can do the calculation. Hope this helps.
Hi!
So you have 458.56 ppm. I think the lab meant 458.56 mg/L = 458.56 ug/mL (ppm will only be equal to these units if the density of the solution is exactly 1).
Your whole sample was in the final 25 mL of solution, thus the total amount of analyte that came from your particles = 458.56 x 25 = 11464 ug = 11.464 mg.
Because your analyte came from 10 mg of particles, this means that someone screw up, because you can not have 11.464 mg of something coming from a total sample of 10 mg.
Hope this helps.
Cheers!
@Mário Silva Thank you so much for the answer. Even I have come down to the same calculations as you suggested. Some error in weighing or dilution of sample must have led to this answer.
Thanks, no problem!
What you say is plausible, however don't discard possible contamination during sample treatment and handling. You don't specify which species was being targeted, but from own experience, some metals can be a real pain because they're very abundant.
Cheers
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