If i am studying the pharmacological actions of 2 drugs and they showed 3 different therapeutic actions e.g Anti inflammatory , Antioxidant, and anti apoptotic actions
How to determine statistically which action is the lead action and more dominant over the other 2 other actions in each drug?
You can determine the lead action of each drug on basis of their dose dependent activity. Therapeutic Index (TI) was frequently determined in animals as lethal dose (ED) of a drug for 50% of the population (LD50) divided by the minimum effective dose (ED) for 50% of the population (ED50).
TI=LD50/ED50
So, after having all actions ( anti-inflammatory , anti-oxidant, and anti-apoptotic) TI data you can compare them. The bigger TI data indicates the lead action of the drugs. Good luck!
I would imagine that each of these actions should be subjected to a comparative study in each of these categories against a leading prototype of the respective actions. The action that stands out should be the dominant action of the compound concerned.
If you want to know statistically which drug is more effective using the values of the three anti-inflammatory, antioxidant and anti-apoptotic actions. Perform an analysis of PERMANOVA One-way and Two-way. NPMANOVA (Non-Parametric MANOVA, also known as PERMANOVA) is a non-parametric test of significant difference between two or more groups, based on any distance measure (Anderson, 2001). NPMANOVA is normally used for ecological taxa-in-samples data, where groups of samples are to be compared, but may also be used as a general non-parametric MANOVA. NPMANOVA calculates an F value in analogy with ANOVA. In fact, for univariate data sets and the Euclidean distance measure, NPMANOVA is equivalent to ANOVA and gives the same F value. The significance is computed by permutation of group membership. Pairwise NPMANOVAs between all pairs of groups are provided as a post-hoc test. Significant comparisons (at p
Enrique Reynaldo de la Cruz Walisinghe Pathirana Nodirali S. Normakhamatov
Thanks very much!!! This is very helpfull
I will try to figure it out accordingly
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