As I diluted my sample from 1 molar to 100 ppm for HPLC analysis, Now if i want to correct my results from 100 ppm to 1 molar what will be the analytical method for that?
Calculate dilution factor. Multiply the result by this value.
Regards
GB
Assuming your detector and injector are linear (a good assumption for HPLC), then the dilution is;
M solution = (grams/MW)/1 L = (1,000,000 x ug/MW)/ 1 L
100 ppm = 100 ug/mL = 100 ug/ 0.1 L
We have to know the 'Molecular Weight' of your molecule of interest in order to perform the calculation. I just gave you the equations necessary to do this calculation.
Why is this question on research gate? This is a General Chemistry or a Quantitative Analysis course question.
Anurag,
More information is needed before I can respond adequately. Is your HPLC method using an external standard with your sample? If so, your HPLC software will be able to calculate your sample (unknown) concentration based on peak responses (sample and standard), the final concentration of your standard and the dilution factor of your sample.
Your software test method and report method should have entries for standard concentration and sample dilution factor. Calculation of the sample concentration is straight-forward:
Sample conc, = (Ru/Rs) x Df x Std. conc.
Regards,
Chris
Anurag,
See ICH Q2 and Q3 on the requirements that need to be validated and develop your method to meet them. The FDA issued a white paper on the chromatography requirements in 1994. Take some courses from chromacademy.com !
How to dilute a sample if its initial concentration is not known, for example i am having an extraction sample of diethylamine in water but i don't know the concentration of diethylamine in the solution so if i want to dilute it for further analysis then what would be the procedure?
Typically, as part of method validation as per ICH Q2, you have already demonstrated a positive relationship (linear most commonly) between mass (as concentration, whether mg/L or ug/mL..) and peak response. Therefore;
(total volume of sample)/(total volume of aliquot) x concentration = mass
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