As the article Article Ligands for CsPbBr 3 perovskite quantum dots: The stronger the better?
reported,Reaction Yield= mpurified*w%/n*MPb
where mpurified is the mass of the dried quantum dots, w% is the mass
percentage of lead (28.74 %) [by inductively coupled plasma optical
emission spectroscopy (ICP-OES) elemental analysis], n is the number of
CsPbBr3 quantum dot moles, and MPb is 207.
n should be the moles of Pb precursor according to "The reaction yield is assessed in terms of Pb present in the DBSA-QDs compared to the Pb precursor."
Hagar Sabry In some article, the number of QDs are generated by the amount metal (for example, Pb of PbS), the amount of metal was acquired by ICP-OES, the tecnique can't acquire good non-metal data (for example, S of PbS, burning to SO2 and gone). So the number of QDs was so ideal, what if the PbS composment of Pb2S3, that is not real. As for the number of QDs synthesized, the article used the amount of Pb which were put into the synthesis solution to generate the number of QDs synthesized, generally speaking, the amount of Pb were usully not eual to the amount of S, usully bigger than S, so the amount of S should be used to generate the number of QDs synthesized. That is not so good way to calculate the yield of QDs.
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