Hello Athira Ishak

0.1 g of Metformin Hydrochloride was shaken with 70 mL of water for 15 minutes and diluted to 100ml D/W. So the resultant solution will be 0.1g/100ml. i.e. 1mg/ml (say solution A).

Solution A was then diluted 1:10 (twice). So the dilution factor is 100.

Best.

To calculate the dilution factor for this assay, you need to take into account the total volume of the final solution and the initial volume of the solution containing the Metformin Hydrochloride.

First, you need to find the initial concentration of Metformin Hydrochloride in the solution. This can be done by dividing the weight of Metformin Hydrochloride (0.1 g) by the volume of the initial solution (70 mL):

(0.1 g) / (70 mL) = 0.00143 g/mL

Next, you need to find the final concentration of Metformin Hydrochloride in the solution after the first dilution. This can be done by dividing the initial concentration by the dilution factor, which is the ratio of the final volume to the initial volume:

0.00143 g/mL / (100 mL / 70 mL) = 0.00143 g/mL / 1.428 = 0.001 g/mL

Then you will repeat the same steps with the next two dilutions:

0.001 g/mL / (100 mL / 10 mL) = 0.0001 g/mL

0.0001 g/mL / (100 mL / 10 mL) = 0.00001 g/mL

The final dilution factor is the product of all of the dilution factors from each step: 1.428 x 10 x 10 = 1428 So the final solution is 1428 times more dilute than the initial solution.