Depends on what panel you want to use. Basically you take your solar radiation data (W/m2) - per unit of time. This means that if a site gets 1000W/m2 of irradiation, the energy falling onto that surface in 1 hour is 10kWh. If you have a panel that is 1m2 and has a conversion efficiency of 10%, then what you could get out of this surface area usefully with the panel is 1kWh. You will also need to adjust for the fact that you won't be covering the ground flat-out with panels, so there will be some "coverage factor", e.g. out of 100m2 area, only 70% will be covered with useful photovoltaic cells.

You simply can also estimate it by using the collecting area and the mean efficiency as:

Power=Radiation*Area*efficiency

Efficiency maybe taken from 10% to 14% typically.

This will depends on your location, type of collector, installation angle and clean PV array.

yes I agree with all of you.

I know the location and I have all other information just want to know the right method and equation to use for this type of calculation.