Hi All,
I got confused in finding the proper method to calculate the kWh(Energy) that can my solar concentrator produce in a certain location.
I 've got the Peak Sun Hours (PSH) calculated which is 5 kWh for a specific month, as well as the power production from this concentrator in lab experiment at different angles.
This concentrator has an acceptance angle of 30 degrees.
I want to convert the power that I know from this concentrator to a real energy if I place the concentrator in a specified location.
Looking forward to seeing your replies
Mazin
Depends on what panel you want to use. Basically you take your solar radiation data (W/m2) - per unit of time. This means that if a site gets 1000W/m2 of irradiation, the energy falling onto that surface in 1 hour is 10kWh. If you have a panel that is 1m2 and has a conversion efficiency of 10%, then what you could get out of this surface area usefully with the panel is 1kWh. You will also need to adjust for the fact that you won't be covering the ground flat-out with panels, so there will be some "coverage factor", e.g. out of 100m2 area, only 70% will be covered with useful photovoltaic cells.
You simply can also estimate it by using the collecting area and the mean efficiency as:
Power=Radiation*Area*efficiency
Efficiency maybe taken from 10% to 14% typically.
This will depends on your location, type of collector, installation angle and clean PV array.
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