I used 0.5 M NaHCO3 fumigation extraction method to determine SMBP but what is the exact equation to calculate the recovery percentage (R)? For recovery calculation I used 250 ug/ml KH2PO4. I found different equations for the calculation of SMBP are as; 1. SMBP (mg/kg) = (Pf - Pnf)/(0.4 x R) R = (P spike - Pnf)/25 *100 2. SMBP (mg/kg) = (Pf - Pnf)/0.4 x (100/R) R = (P spike - P nf)/(P spike) * 100 3. SMBP (mg/kg) = (Pf - Pnf)/0.4 x (100/R) R = 100 * (P spike - P nf) /250 I put all the possible equation for the calculations of SMBP (I tried all these equation for my data with different answers), now I want to know which equation is the best for the calculation of SMBP, particulary I am mch confused for the calculation of Recovery (R)? Please experts, give your comments? and what should be the range of SMBP in crop land and C:P ratio?
Which equation reveals a minimum difference in C: P ratio between soil C:P ratio and soil microbial C : P ratio...should invariably considered an ideal equation in predicting soil microbial C: P ratio...
This paper will probably be helpful
Kouno, K., Tuchiya, Y., & Ando, T. (1995). Measurement of soil microbial biomass phosphorus by an anion exchange membrane method. Soil Biology and Biochemistry, 27(10), 1353-1357.
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Biomass P is calculated from difference between the amount of inorgarnic P ( P ) extrcted by 0.5 ( Spm ) NaHCO3 ( pH 8.5 )from fresh soil fumigated CHCl3 and the amount from unfumigated soil. For more details consult hhttps://www.sciencedirect.com
Muhammad Qaswar, this article will help you to understand SMBP in relation to C,N,P,S ratios
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