I know how to calculate areal loading or mass of Li anode (because Li is fabricated commercially as foils with known thicknesses (µm)) as follows
0.1*Density*Thickness
where
thickness is given in µm
For cathode should I calculate it the same way? In that case if I use density of cathode active material the thickness still includes other materials such as binders and electronic conductors. How to account for them? Or should I use weighted density of total cathode including everything?
Or should I calculate areal mass or loading by calculating percentage of cathode active material and divide it by calculated area of coating?
Clear and concise answers would be highly appreciated. Thank you.
If you use 3-electrode system, mass of a single (working) electrode is taken into account. In the case of "real" supercapacitor (2-electrode cell), both electrode masses are required to know. BUT if you going to compare the capacitance (or energy) of your supercapacitor to the specific capacitance (or energy) of commercial cells, you have to divide it by the mass of whole device including the masses of a metalic current collector, separator, electrolyte, etc.
measure weight of the electrode before and after coating. Difference will be the mass. devide with area. that will give g/cm2.
use cv curve to calculate capacitance. meaure the area of the exposed surface. get C/cm2
specific capacitance will be C/cm2/g/cm2= C/g
Yes, you can calculate the mass (in mg) of the current collector before and after loading of active materials precisely and divide by the mass loading per area (usually using 1 cm2) easily by calculating the area of the current collector in cm2.
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