If I have a cathode capable of ~500mAh/g
and an anode of ~300mAh/g for example,
For 2g of active material (assuming a 1:1 ratio, although impractical - 1g cathode material and 1g anode material), will I have 300mAh of total reversible capacity since the anode is a limiting case? Or will the capacity be an addition of 300mAh + 500mAh = 800mAh?
This is ignoring electrolyte and other components, I just need to know the basics of the theory. Thanks in advance.
Dear friend Jon Lees
To calculate the total capacity of a battery, you need to consider the reversible capacity of both the cathode and anode materials. The reversible capacity of a material is the amount of charge that can be stored and released during the electrochemical reaction without causing irreversible damage to the material.
In your example, if the cathode material has a reversible capacity of 500 mAh/g and the anode material has a reversible capacity of 300 mAh/g, then the total reversible capacity of the 2g of active material will be the sum of the reversible capacities of both materials, which is 800mAh.
However, it is important to note that the actual capacity of a battery will be lower than the reversible capacity due to factors such as electrode degradation, electrolyte resistance, and other losses that occur during charge and discharge cycles.
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