I had performed cellulase activity checking based on Ghose, T.K. (1989) protocol. The enzyme activity was determined at 121.0 FPU/ml (at 0.0030 Ezy concentration).
1. What does it mean?
2. How many ml of enzyme (at 0.0030 enzyme concentration from 1:20 stock dilution) that need to add-in to degrade 5% (w/v) biomass at final volume of 50ml?
Thank you.
Anton Ross
FPU means filter paper units. Filter paper (usually Whatman No. 1) is used as substrate and the amount of deliberated sugars is measured. The measurement method is classically the measurement of reducing sugars, but a modification uses HPLC instead. 1 FPU/ml means that the equivalent of 1 µmole glucose is formed per min and per ml enzyme solution under given test conditions.
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