Since i am using SIMP model, i should be getting a continuous values of the densities from 0 to 1. I want to know what are the elements density values that are results from the abaqus TO? Does the shown elements material means its all 1 and the removed elements material is 0?
Also, if somebody knows how Abaqus SIMP works or an explanation about it that would be very helpful.
i worked on Abaqus in final level and know something but i dont know SIMP would you please tell me more about it to know what you mean to help you dear friend
tnQ
If I understood you are looking for an introduction to the material property "interpolations" used in Abaqus ATOM (SIMP and RAMP).
For an idea on how Abaqus SIMP works and an explanation about, e.g. try to see it at "section 2.2.2.1 SIMP-model" of the document http://www.diva-portal.org/smash/get/diva2:648664/FULLTEXT01.pdf
A value 0 is not used for the relative densities but instead a rho_min= 0.001 (default in Abaqus ATOM but can adjust it).
Hope that others with more experience may here improve the help on this subject.
Hello Arash and Miguel,
Thank you both for your kind replies. To answer your comments respectively here is the following:
There are different techniques or methods for topology optimization such as Solid Isotropic Microstructure with Penalization (SIMP). Regardless of the technique Abaqus follows an optimization criteria to find the optimal density material distribution of the given design domain (topology).
These densities ranges from 0 to 1 but in the case of Abaqus optimizaiton techniques the density has to be a non-zero value, so as Miguel suggested as an Abaqus default it would be from 0.001 to 1 in a continuous distribution. So that means there are material densities in the resulted topology optimization that would be a fractional value from 0.001 to 1.
What I want to do is visualize these fractional material densities of the resulted TO elements distribution and know the value of each element material density.
I hope this explains what i need more, thank you again for your comments.
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