Why depletion region (i.e. built-in potential) in Schottky contact is smaller than the pn junction? In other words, why Voc of Schottky contact is smaller than the pn junction?

Does it have any relation with the types of charge carriers in these junction. I mean, since only electrons are the charge carriers in Schottky contact, therefore, the built-in potential is lower than the one in pn junction, where both electrons and holes are charge carriers and create stronger depletion region?

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