my some questions whose confuse me
1. in literature some researcher says we can calculate the specific capacitance in unit of F/g by using three electrode system by equation which is given below:
integrated area on the curve cv/ 2* mass* potential window* scan rate
but some researcher says we can calculte the specfic capacitance in unit F/g by using three electrode system by equation which is given below:
integrated area on the curve cv/ mass* potential window* scan rate
but not divide by 2 . which one is correct ?
2. area under the curve is calculated in cv all of its parts mean capacitive current , faradic current , anodic and cathodic or only anodic part i upload a cv curve with its part ?
3. who can we calculate the areal capacitance of electrode if i deposited the active materiel on nickel form area 1 cm2 on the both sides ? my question is that we divide the capacitance by 2 or 1 in replace of mass in above equation.
4. in gamry software we calculate area under the curve of unit coulomb but this can not satisfied the above equation such as
Cs = coulmb/ gram* volt* milivolt/ second = coulmb *time /gram* (volt)2
which is not equal to F/g why ?
The CVs for capacitance calculation must be rectangular, or approximately rectangular. Peak-shaped CVs as the one shown by you are non-capacitive and should not be used for capacitance calculation.
As for the two equations, both are correct, but the first one refers to the whole area of that enclosed by the CV, whilst the second one is for integration of only a half of the CV, either the forward or backward scan.
The CVs for capacitance calculation must be rectangular, or approximately rectangular. Peak-shaped CVs as the one shown by you are non-capacitive and should not be used for capacitance calculation.
As for the two equations, both are correct, but the first one refers to the whole area of that enclosed by the CV, whilst the second one is for integration of only a half of the CV, either the forward or backward scan.
Have a look at the methods discussed here:
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