This is in addition to Prof. Jacholkowski and Prof. Strokovsky answers.
The definition of stripping reaction, just in case.
Stripping reaction, in nuclear physics, process in which a projectile nucleus grazes a target nucleus such that the target nucleus absorbs part of the projectile. The remainder of the projectile continues past the target. An example is the (d, p) stripping reaction involving an aluminum-27 nucleus and a deuteron. The deuteron (consisting of one proton and one neutron) grazes the aluminum nucleus, which captures the neutron to become aluminum-28, and the proton continues on with a velocity comparable to that of the incident deuteron. (Encyclopedia Britannica).
Stripping reactions with deuteron as a projectile nucleus are denoted as (d,n) or (d,p). Reactions (d,p) has a lower threshold comparatively with (d,n). Why? Coulomb field of the target nucleus does not affect the neutron, but repulses the proton. In deuteron the distance between nucleons are large, and the neutron manages to penetrate into the nucleus before the proton which passes the time overcoming the Coulomb barrier. As a result the deuteron breaks. After this the proton cannot penetrate into the target nucleus due to the Coulomb repulsion (if the deuteron energy was comparatively low).
In case of light nuclei the stripping can be slightly favored for protons due to the additional electromagnetic interaction (with charged particles of course) which is absent for neutrons. For heavier nuclei the situation becomes more complicated due to the neutron skin effect, that is an excess of neutrons on the nucleus surface while the stripping reaction is related to peripheral collisions.
Experimentalists will answer you immediately: because it is much easier to detect protons and measure itheir momenta, then to measure the neutron momentum.
Deuteron stripping is one of the chip methods to obtain narrow, almost monoenergetic beams of neutrons, which cannot be accelerated directly.
Dear Adam, you did not answer the question "Why is proton stripping reaction more favorable as compare to neutron stripping"? In your example you are speaking about a way how to get a quasi-monochromatic neutron beams using deuteron breakupb reaction. The method is exploited since (may be) 40 or 50 years to produce neutron beams!
But the question under discussion is also not correct: literally speaking, when we produce neutron quasimonochromatic beams, we are stripping DEUTERON, not PROTON and get either a neutron beam or a proton beam. The point is: who is a spectator (i.e. the produced beam particles)? So, Mr. Sahoo should reformulate his question and clarify, what HE means saying "proton stripping reactions". Does he mean a reaction with the proton as a projectile?
This is in addition to Prof. Jacholkowski and Prof. Strokovsky answers.
The definition of stripping reaction, just in case.
Stripping reaction, in nuclear physics, process in which a projectile nucleus grazes a target nucleus such that the target nucleus absorbs part of the projectile. The remainder of the projectile continues past the target. An example is the (d, p) stripping reaction involving an aluminum-27 nucleus and a deuteron. The deuteron (consisting of one proton and one neutron) grazes the aluminum nucleus, which captures the neutron to become aluminum-28, and the proton continues on with a velocity comparable to that of the incident deuteron. (Encyclopedia Britannica).
Stripping reactions with deuteron as a projectile nucleus are denoted as (d,n) or (d,p). Reactions (d,p) has a lower threshold comparatively with (d,n). Why? Coulomb field of the target nucleus does not affect the neutron, but repulses the proton. In deuteron the distance between nucleons are large, and the neutron manages to penetrate into the nucleus before the proton which passes the time overcoming the Coulomb barrier. As a result the deuteron breaks. After this the proton cannot penetrate into the target nucleus due to the Coulomb repulsion (if the deuteron energy was comparatively low).
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