Will you record the same emission peak regardless of the excitation wavelength?

My suspicion is that you are observing the Raman scattering of the solvent. The Raman scattering wavelength will change when changing excitation wavelength. The shift will be constant (in wavenumber).

Otherwise you might have a fluorescent contaminant.

You should record the spectrum with different excitations and if the emission peak position also changes accordingly (mentioned by @Nils Carlsson) you are observing Raman scattering. which I also encounter with Water (3000 /cm) as solvent especially in very dilute solutions.

I agree with the two previous answers and call your attention on the remark by Nils: alcohol sold for purposes other than producing various drinks (which usually is subjected to taxes) contains a denaturant which might be an aromatic compound (e.g. camphor, phthalate, thiophene...) which is fluorescent. In case this should be indicated on the label.

Hi, most probably you have detected an emission from impurities in EtOH, or a peak coming from the excitation source. First, measure carefully the UV/Vis spectrum of EtOH to exclude impurities.

It is highly recommendable to use solvents, which are specifically validated for your intended purpose. The purity can be very different. For spectroscopy, special grades are available, such as

https://www.sigmaaldrich.com/catalog/product/mm/100980?

Lab grade or even AR grade ethanol has quite often been "dried" (to remove water) with benzene added during the distillation process. Distillation without benzene yields only ~90-95% ethanol, the remainder being water that distills with ethanol as an azeotrope. Hence the use of benzene. Thus a fluorescence spectrum of "pure" ethanol will probably be due to the presence of a percent or even much less of benzene, solution fluorescence maximum around 28nm:

That should of course read 286nm, not 28nm for the fluorescence maximum!