Which component E or B of an electromagnetic wave is responsible for visible effect?
E, B can be understood as a relativistic correction for E. So, even if I’m not sue I got the question correctly, the answer is E in any case :)
What do you mean by "visible effect?" Maybe you are asking what you visually see? That is more of a frequency thing. Your eyes are only sensitive to the visible spectrum. I know little about the eye, but I suspect they are actually detecting the E component of a wave.
Maybe you are asking whether it is E or B that interacts with something that can be observed? If so, it depends on what that something is. If you are looking at a compass needle, that responds to B.
Both previous answers are correct. They are also correct in asking you to clarify your questions. Neither of the previous answers explicitly mentioned photons (quanta) or the Poynting vector. Whatever you are trying to ask the answers will probably involve all of the above. Do not give up - try again! People want to help!
I think the two components Electrical (E) and Magnetic (B) is responsible for visible effect, but this is relative depending on the nature of the radiation source. so according to your problem. I suggest you to give more details on your problem.
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