LAH reduce α,β-unsaturated ketone. But what will be the product of such extended conjugated system? Will here also LAH reduce all the double bonds along with carbonyl group?
Hi Mondal,
You will get same cyclohexanol,if you are using enough amount of LAH,use excess LAH if you want cyclohexanol. Good luck
LiAlH4 predominantly reduces the ketone first before the conjugated double bond. Without the ketone, the enone reduction cannot occur with LiAlH4, Typically another metal salt is needed to tune the reactivity of the reducing agent for conjugate reduction.
http://pubs.acs.org/doi/abs/10.1021/ed058p628
for the 2nd compound the diene-ketone I highly doubt you will be able to find much of it, the enol tautomer should be much more stable for this, several orders of magnitude I will expect
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