The fill factor is never equal to one in solar cells and this feature decreases the solar cell's power efficiency. In the equivalent circuit of all kinds of solar cells, even if the shunt resistance is considered infinite and the series resistance is considered zero, the fill factor can never be one because of the exponential waveform of the diodes' I-V curve. The area of the rectangle with surface area of (Impp)*(Vmpp) is always smaller than that of (Is.c)*(Vo.c). The difference between these two areas is both because of losses of resistances and the difference between the exponential I_V curve of the diode and the rectangle with (Is.c)(Vo.c) surface. I know that the portion of this difference due to the nonzero and finite values of series and shunt resistance is converted into thermal energy. But I cannot understand that what type of energy the portion of optical energy lost due to the difference between exponential and rectangular curves, is converted to?

Thank's.

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