In the figure a second order differential is obtained for a RLC circuit with DC source in series.
What is the significance of it when we have a capacitor in series? Why this circuit is not treated as an open circuit?
In this circuit i should be '0' then How the voltage in R is taken as V=i*R?
Hello Vibha,
the ODE describes the circuit generally, also in dynamical states and transient response. Of course, in steady state, the capacitor's voltage is equal to the source voltage and the current is zero. But if you want to know what happen when e.g. the the source is connected, you can use this ODE.
The importance of this circuit is when there are swiching circuit charge and discharge the inductor and capacitor. Yet by this math way we calculate the impedance and take all componants in consideration no matter the status of steady state, charging or discharging.
Your conclusion about the current flow on the circuit is valid only in the steady state operation; however, in the transient period i.e. just after the energization of the circuit the capacitor current will not be zero provided that it was not initially (i.e. before energizing the circuit) charged to the value Vo with the given polarity. I guess a switch is missing from the circuit layout.
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