I'm confused with the multiplication factor of 2 and 4, kindly explain.
Dear Tapas Das,
If you want to calculate specific capacitance using CV then you have use following equation,
Csp = Area under the CV curve /2(scan rate x voltage window x mass of electrode)
and For charge discharge measurement,
Csp = current x discharging time/voltage x Mass
for more details you have to read any research paper related to supercapacitor application
Thanks Madagonda Vadiyar. So no need to multiply by factor 2 or 4. I was confused about that thing. I have gone through some papers, there they have not mention clearly that it is multiplied by factors or not. maximum papers they have studied by two electrode only.
Thank You Sir
if you are measuring in three electrode system, then you are performing the analysis in only one electrode, so there is no question of adding and factor of 2 or 4.
in case of two electrode system, there are two types of capacitance is measured. one is device capacitance, where no multiplication factor is used. but in general the researchers used to measure specific capacitance of a single electrode in two electrode system, so you have to use multiplication factor. now if you consider the mass of single electrode, then the factor is 2 and if you consider total mass of both electrode then the factor is 4.
Thank You very much Sir,Dhrubajyoti Bhattacharjya, for your valuable discussion. Now it is clear to me not only how to calculate specific capacitance for three electrode system but also the use of factor 2 and 4.
I have a confusion regarding your answer Dhrubajyoti Bhattacharjya. Why there is need to use the factor 4 while calculating specific capacitance on the basis of two electrode system if total mass of both electrodes is used in the following formula:
Csp= I dt/m dV
Can you please provide references for the same...
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