I am aware that we should use the t-test for comparing means when the sample size is small and when we do not know the SD of the population and that , the z-test is to be used for comparing means when we have a large sample size and the SD of the population is known.

Now, my sample size is - 400. I don't know the population SD (and I simply cannot understand how is it ever possible to know the population SD, please forgive me for my ignorance and lack of knowledge).

What I do know is, that after data collection I can conduct the Kolmogorov-Smirnov test and the Shapiro-Wilk test(on SPSS) to determine if my sample is a normally distributed one.

I can even check for homogeneity of variance.

But, I will still never know the population SD.

If the sample is a normally distributed one, should I proceed with the z-test? (in spite of not knowing the population SD) or do I just stick to the t-test?

Any help from Professors and fellow researchers will be greatly appreciated!

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