Giving the construction of Reynolds stress tensor there some basic constraints which limits how the values for components may assume in a given realisable flow. I currently have no problem understanding that

- the Reynolds stresses are positive semi-definite;

- and have both first and second invariants greater than zero, due to results in functional analysis.

However, I am failing to see why should also the determinant of R be also a positive (or zero) quantity. At the appendix in Schumann's paper there is such a proof, but I didn't quite well follow all his steps in the demonstration.

Has anyone ever demonstrated somewhat differently than Schumann's version? I mean, in a more geometrically way?

Best regards to all and thanks in advance for any advice,

Fernando Soares.

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