Giving the construction of Reynolds stress tensor there some basic constraints which limits how the values for components may assume in a given realisable flow. I currently have no problem understanding that
- the Reynolds stresses are positive semi-definite;
- and have both first and second invariants greater than zero, due to results in functional analysis.
However, I am failing to see why should also the determinant of R be also a positive (or zero) quantity. At the appendix in Schumann's paper there is such a proof, but I didn't quite well follow all his steps in the demonstration.
Has anyone ever demonstrated somewhat differently than Schumann's version? I mean, in a more geometrically way?
Best regards to all and thanks in advance for any advice,
Fernando Soares.