Hi,

Its a double scalebar. First you measure your scalebar and then measure the recording.

Lets say the horizontal bar is 5cm. That 5cm correspond to 1min. If you measure your whole recording is 21cm, which translates to 4.2min.

The same goes for the vertical axis. 5cm is 10mV. So the amplitude of your spikes (12cm) is 24mV.

The scalebars are irrespective to the electrodes. First you take your recording (with any number of electrodes), and then you put the scalebars on the recording.

Hope this helps

Hi, just to add some info, the trace with the scalebar shown (in mV units) appears to be in current clamp. If you have a voltage clamp recording, it will be measuring current, so it will be pA or nA units. Usage will still be the same as Demos explained.

hello,

sorry but I miss something or I think that something is wrong in your question or in your recording. According to Ohm’s law (V=I·R) If you are recording mV (millivolts), you are not in voltage-clamp, you must be in current-clamp. If you were in voltage-clamp, your recording would be current, expressed in milliamps (mA).

Sincerely,

Oscar

Oscar Casis Apostolos Mikroulis

Thank you to both of you :) I picked a lookalike picture and

didn't notice about it, thanks for the kind reminder