Hi, I guess it depends on what you want to do? Will you consider buckling? Plane stress or Strain can't do that.

Plane Strain is good for stuffs like Long pipes and plane stress for Thin members. According to the dimension, it seems like its a thick beam. But not thick as a pipe! Ill go with Plane stress taking 1800x250 part into modeling.

Hi Hasnat Ahmed

It depends on what you want.

But in general, Because there are no stress variations along the width of the beam, the assumption of plane stress can be used. However, there is a strain due to the effect of Poisson.

Hasnat Ahmed Can you not just run 3D, if this is your only part?? At least as a start, and then compare to the two suggested approximation for your particular application.

Hi Hasnat Ahmed

I am assuming that you are attempting to specify material property. Based on a sensible guess, the beam is hollow and the thickness of the section would be comparatively thinner than the general geometry, at least 1/15 or less.

If the section thickness is relatively thin, a plane stress property should give sufficient representation of the experiment, although plane strain should give a more conservative estimation in yielding. You could do a quick analysis with shell elements testing both settings, although I doubt there would be much difference between.

Hope it helps.

Regards,

Wee

Hi Hasnat, your question is not self-explanatory (what you mean actually). However, if you want to calculate buckling/deflection under loading - you may consider a plane stress element.

plane stress in one in which stress along z-direction(out of plane) is ZERO and a plane strain condition is one in which strain associated along z-direction(out of plane) is ZERO.

For your problem you better do a 3d analysis.

Plane stress in which one of three stresses along z-direction(out of plane) is ZERO and a plane strain condition is one in which strain associated along z-direction(out of plane) is ZERO.

Plane stress condition can be visualized as thin plate with stresses acting along its plane. There is no stress acting perpendicular to to the the plane and (∂/∂z)(∂/∂z) components in equations are zero.

Plain strain can be idealized as long wire with stresses acting perpendicular to its length. Therefore the strain or displacement along the length is zero. Again (∂/∂z) components in equations are zero.