I have to do few toxicity tests in which silver is involved. To do that i have to prepare a stock solution using silver nitrate (AgNO3) salt. The concentration of exposure in the tests is referred to silver itself, not to the compound. I need to know how much silver nitrate salt i need to have the concentration of 5 g/L of Ag. I would be really glad if someone could also explain/show the mathematical and logical reasoning behind the answer.
5 g Ag / L means 0.5 g Ag / 100 mL if ypu want to do it on a smaller scale. The atomic mass of silver is 107.87 g / mole, i.e. you need to have 4.63 mmole Ag / 100 mL solution. The molar mass of silver nitrate is 169.87 g / mole. Thus you should just weigh out 0.786 g AgNO3 (= 6.63 mmole) and add water until you have 100 g of solution.
Frank T. Edelmann and Dariusz Matoga thanks a lot, i really appreciated your support!
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