Dear All,
Currently, I am trying to understand the lead equivalency subject. That is, I have data for my glass series in terms of commonly investigated radiation shielding parameters (i.e. linear attenuation coefficient), and I want to convert this data to lead equivalent thickness. Therefore, is there anyone who can help with this conversion? I can give some data about half-value layer thickness for my glass series as below:
Code-1: 2.60 cm
Code-2: 2.45 cm
Code-3: 2.21 cm
Thanks in advance.
Is the radiation you are assuming continuous spectrum x-rays from an x-ray tubes, or line spectrum gamma-rays from radioactive isotopes? In either case, I think information on the energy/maximum energy is required for further consideration.
By the way, are the values of Code-1, 2, and 3 results of simulation? If so, wouldn't it be easy to change the material of the shielding to find equivalent thickness?
Dear Kengo Shibuya ,
Many thanks for your kind response. Actually, the HVL thickness values are derived from the linear attenuation coefficient which is experimentally measured with the use of Cs-137 (0.6617 MeV). Therefore, we are dealing with experimentally measured gamma-rays results, not simulation data.
Dear Recep Kurtulus ,
Thanks for your reply. It turned out to be a simple case.
For example, how about the graph on page 15 of the following document (50% attenuation)? Of course, the values may vary slightly depending on the experimenter or the method of calculation, as you show with the three numbers.
[Daniel R. McAlister, Gamma Ray Attenuation Properties of Common Shielding Materials]
https://www.researchgate.net/publication/266500546_Gamma_Ray_Attenuation_Properties_of_Common_Shielding_Materials
Other examples,
[Measurement of Shielding Effectiveness of Building Blocks against 662 KeV Photons]
https://www.researchgate.net/publication/306342783_Measurement_of_Shielding_Effectiveness_of_Building_Blocks_against_662_KeV_Photons
[Comparison of Lead and WC-Co Materials against Gamma Irradiation]
https://www.researchgate.net/publication/261697810_Comparison_of_Lead_and_WC-Co_Materials_against_Gamma_Irradiation
[Measurement of Shielding Effectiveness of Building Blocks against 662 KeV Photons]
https://www.researchgate.net/publication/306342783_Measurement_of_Shielding_Effectiveness_of_Building_Blocks_against_662_KeV_Photons
Dear Kengo Shibuya
Your suggestions are very valuable for understanding the behavior of lead against Cs-137 irradiation. It is also clear to see the values for parameters, i.e. half-value layer at 0.662 MeV. However, if I find out a simple conversion to figure out the lead-equivalency for my glass series, I will be able to convert the values at different photon energy levels. Hope that I am clear about what I am trying to understand.
Transparent radiation shielding protects the experimenters and medical personnel. I wish you all the best in your research (adding new lines in the graph). See you.
How about the thickness of the sample？That is mean the same shielding efficiency of the sample and the lead. For example, 1 cm lead, 50％, and the same 50 ％ need about the 10cm of the samples you prepared. Maybe this will be useful for you.
Dr Dong, mg_dong#163.com, mgdong229@gmail. com, Northeastern Univeristy
Dear Mengge Dong
With reference to the thickness of samples, you may find them around 8 mm (tolerance of +- 0,25 mm). However, I could not comprehend the conversion of the lead-equivalency of my glass series.
Dear Mengge Dong , I will contact you by e-mail, thanks a lot for your kind interest.
am mr henry okafor ,a lecturer in benue state university Nigeria and Ph.D student in view
Article SU‐D‐134‐04: On the (f)utility of Measuring the Lead Equival...
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