Compare to C-D bond O-D bond is weaker. According to catalytic cycle (attached below) O-D bond cleavage is not occur? Could please explain the reason?
Reaction condition: Pd(OAc)2/ Catacxium ligand, K3PO4 base, CD3OD, 80 oC
Do you believe in this catalytic cycle? Has it been proven? In addition, I do not fully understand the question since there is a cleavage of the O-D bond! Please keep also in mind that, in presence of the phosphate base, methanol might become (partly) deprotonated.
Hello!
Have you tried CD3OH or CH3OD to confirm it's the C-D bond only and not the O-D bond? It's not necessary BDE-driven because the chemistry is 2-electron processes, not radical chem.
Beta-D elimination (and the corresponding beta-H elimination) has been seen before at Pt and Pd. See the intro and discussion of my Pt paper, we cite a Pd example (see Figure 3), check that Pd paper our and forward search it to to see other examples. Article Reductive Elimination and Dissociative β-Hydride Abstraction...
If you need access to the article, I can send you a copy.
Sincerely,
Kyle Grice
Hi! kyle Grice
We have done CD3OH and CH3OD experiments. It was published in below attached publication. Not only, my work M.Beller also published similar kind of mechanism for his C-O cross coupling reaction. My question is, why the deuterium exchange was not happen from weaker O-D bond. Why it's not dominating the BDE process. Is there any specific reason?
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