I have studied the photodegradation of MO dye by using ZnO as a catalyst and then investigate its catalysis performance based on the degradation efficiency values. Is the degradation efficiency and absorbance efficiency the same in this case?
Catalytic dye degradation involves visible light absorbance but its rate/efficiency cannot be directly related, since formation of super-oxide and peroxide molecule also leads in dye degradation therefore researchers use scavenging agents to suppress formation of such molecules so that whole degradation can take place due to catalyst. Although you can characterise for absorbance and on the basis of absorption coefficient and peak shifting one can say high absorbance will lead to larger electron-hole pair generation and greater redox ability.
So, Brajesh Rajesh Bhagat sir is there any direct formula, for calculating absorbance efficiency?.
For the experimental characterisation follow (Article Measurements of light absorption efficiency in InSb nanowires
) this work while theoretically you can calculate it using absorption by the material and AM1.5 solar spectrum in particular range, i.e., efficiency=total absorbed/total incident. Attached pdf for theoretical calculations.
Hi Sathi,
Definitely not. Each catalyst behaves differently, depending on its surface area, and on the experimental conditions (organic compound on which it will act, buffers present in the solution, energy and intensity of radiation used, etc ...)
No dear.
The absorbance efficiency of any photocatalyst can be calculated by computing the degradation rate of a pollutant in the dark period, prior to the illumination.
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