"primers at a concentration of 10 µmol/L"
"primers at a concentration of 10 mmol/L"
"primers at a concentration of 0.5 μmol/l"
I found this concentration from three different article.
How should I calculate please give me response.
Use the formula C1V1=C2V2 when calculating dilutions. There are online calculators if you aren't confident in your math skills.
Just as a heads up, check if the concentrations in the paper are for the concentration of the primers in the tube of primers ("working concentration") or the final concentration of primers in a reaction.
Most folks dilute their primers to 10 mMol for their "working concentration", but would use 0.5 microliters of that primer in a 25 microliter volume reaction.
Good luck!
Your primer stock is 100nM/ml or 100µM/L so use a 1 in 10 dilution for your 10 µmol/L. Unfortunately you would have had to resuspend your primers in a smaller volume to get the 10mM conc.
Generally the original primer stock (lyophilized) are reconstituted to get 100 uM of primer. I do not understand why people refer to primer as uM/L or pM/mL, a molar solution does not need to be mentioned in terms of per ml or litre.
Use the original stock of 100 uM and dilute it 1:10 (take 1ul of stock and add 9uL of RNase DNase free water) and you will get 10uM working stock of your primers. Usually for a PCR reaction we add about 0.5uL to 1uL of working stock primer in 25uL reaction. Thus the final primer concentration will be 1:25th of working stock - 10/25 = 0.4uM or 400nM. Taq polymerase enzymes require betwee 0.2 um to 1uM of primer. I have suggested 0.4uM for ease of calculation.
All the best.
Thanks.
Prasad.
your primer concentration is 100 pmol/µL equivalent to 100 µmol/L or 1 x 10e-4 mol/L ; to obtain a solution at 10 mmol/L (as mentionned in the question title) equivalent to 1 x 10e-2 mol/L, you must concentrate 100 fold your initial solution!
Herve Levesque Thank you for your reply. I am very much glad and understand the calculation.
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