Proove that the dislocation reaction is vectorially correct a/2[10-1]-->a/6[21-1]+a/6[11-2]...Please solve this and tell me the approach.
Dear Rajorshi, the Burgers vectors are vectors, as the name suggests. So you have to add the two vectors for the partial dislocations, i.e. add each components together:
for instance, for 1st component:
a/6*2 + a/6*1 = 3a/6 = a/2. You get the first component of the non dissociated dislocation. Idem for the other components.
Best,
L.P
Laurent Pizzagalli What if someone asks me to show a decrease in strain energy?
The argument behind the dissociation of perfect dislocation with Burgers vectors a/2 in two partials with Burgers a/6 is related to the dislocation energy which is roughly proportional to the square of the norm of the Burgers vector. Then, for a perfect dislocation, it is a2/2, while for a partial it is a2/6.
Since a2/2 > a2/6 + a2/6, the dissociation is energetically favored.
Best
L.
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