To calculate the real concentration of Mo in your solid sample we need the following information:    The weight of the solid you dissolved...... The final volume up to which you diluted the dissolved material.

You then simply multiply the 366 result with the volume of your solution and divide the product by the weight of the sample you've already dissolved.

OR: simply send me the data I asked above and I will show you how to do the calculations... Good luck

Dear Sir,

Thanks a lot for your reply and helping me.

We have used initially 3 mg of sample and final volume upto ppb concentration.

Ashish... You've weighed 3 mg sample and dissolved it in WHAT? and after that you must have diluted the solution and make up to a VOLUME (How much)? I may then give you the exact result. However, 3 mg is a very small quantity and there must be an error in the weight unless you've used microbalance.  send me the data soon to give your the right answer although I prefer you repeat the analysis with a sample weight of at last 0.05-0.10 g weight to reduce any possible errors.   Regards   

Dear Sir,

             We dissolved 3 mg sample in 1 ml of Aqua-regia and then diluted it to 10 ml

Again took 1 ml from above solution and diluted further to 10 ml . Followed the same dilution process five more times .

Can you tell, how to calculate ?

Ashsh.... Multiply the results by 100 (10x10) and the result has to be divided by 0.003 g.

Sir by this way 365 x 100 devided by .003 will give 12200000.

what does it mean. what will be the metal % in sample. How to make it simple

Ashish... what is the unit of the 365?

Sir Sorry ..it was  actually 366.

366 is the concentration mean, You may have a  look at the other details in attached pdf file,