The range() function can only work with integers (whole numbers, not decimals/floats).

The easiest way is to use numpy.arange or numpy.linspace option and python's enumerate().

Though using nested for loops isn't the ideal case, consider using numpy.meshgrid() and numpy.reshape().

See attached.

see

range function in python cannot take float number as a step value. You can write your own generator or else use numpy like below

import numpy as np

for i in np.arange(0.0,3.0,0.1):

for j in np.arange (0.0,4.0,0.1):

print(i,j)

There are plenty of ways to achieve this (you may also want to use round function to round the resulting float values).

Both proposed solutions work well. The last one the most straight forward and intuitive but as said there are many ways of doing this and the best depends on how you will use the results later. I presume that the print is just to test the structure.

Thank you all for your support.