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Hi Abubakar Abdullahi Lema
To prepare a 1L 1M solution of any substance we need to dissolve 1mole (i.e., the molecular weight) of that substance. Thus, to prepare 1L 1M H2O2 solution one needs to dissolved 1mole of H2O2 i.e., (1*2)+(16*2)=34g of H2O2. As H2O2 is liquid one has to measure this amount in volume with the help of the formula density=mass/volume (at a particular temperature). Thus, one can prepare 1L 1M H2O2 solution at the desired temperature. From this stock solution, one can prepare the 20, or 40 micromolar solutions or any certain strength solution using the V1S1=V2S2 formula. Remember 1micromolar = 10^-6 M
This I can say my the best of my knowledge.
Regards
Abubakar Abdullahi Lema
It may be convenient to make up a 1 M solution as in the above answer and dilute accordingly with DI water. For example, to make a millimolar (0.001 M) solution from a 1 M solution will require 1 mL of the original 1 M solution and 999 mL of DI water. Usually then 1 mL of the original solution will be added to a 1 L standard flask and then DI water added to the mark. This 0.001 M solution could then be used to make micromolar solutions similar to the above (20 mL 0.001 M made up to 1 L with 980 mL water would make your 20 micromolar solution etc).
Note that H2O2 solutions slowly decompose under ambient conditions. The actual concentration would need checking/confirming before use - a colorimetric test would be suggested. For example: https://www.arborassays.com/product/k034-h1-hydrogen-peroxide-h2o2-colorimetric-detection-kit/#:~:text=The%20DetectX%C2%AE%20Hydrogen%20Peroxide,in%20a%20variety%20of%20samples.&text=The%20HRP%20reacts%20with%20the,is%20read%20at%20560%20nm.
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