Dear rg members,
I want to make ammonium thioglycolate 60% solution from thioglycolic acid 80% and ammonia 30% solution ,I want calculation part please help me?
Hi Vasu,
By assuming that all the solutions are expressed in %w/v you need to mix 63.29 ml of thioglycolic acid (80% w/v) and 31.20 ml of ammonia (30% w/v as ammonia instead of ammonium hydroxyde) and complete to 100 ml with water at constant temperature.
Calculations:
If considering 100 ml in each case you have as follows:
Ammonium thioglycolate (AT) 60% w/v:
60.0/109.15 = 0.5497 mol of AT in 100 ml.
In this way, you require 0.5497 mol of thioglycolic acid (T) and 0.5497 mol of ammonia (A).
80.0/92.11 = 0.86853 mol of T per 100 ml and therefore, 100x0.5497/0.86853 = 63.29 ml of T (80% w/v).
30.0/17.03 = 1.7616 mol of A per 100 ml and therefore, 100x0.5497/1.7616 = 31.20 ml of A (30% w/v).
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