Assume,
A=[1 2 3 4]
and I need all probable connection of any two number
like
Answer = [1 2; 1 3;1 4;2 3;2 4;3 4]
or for 3 connections
Answer =[1 2 3;1 2 4; 1 2 4; 2 3 4]
Martin H. Trauth
You wish to get all possible combinations of the elements in A, so you can use COMBNK from the statistics toolbox:
A=[1 2 3 4]
combnk(A,2)
combnk(A,3)
1 votes
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Ghanshyam G. Tejani
Yes this is a perfect solution
A=[1 2 3 4]
combnk(A,2)
combnk(A,3)
Thank You
1 votes
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James F Peters
To obtain the number of combinations, try
C=combnk(1:n,k);
sizeC1=size(C);
sizeC=sizeC1(1); %Number of combinations
For an application of combnk, see page 112 of the attached thesis.
1 votes
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Miguel Belbut Gaspar
If you just want the number of combinations, you can use
m=nchoosek(n,k)
or you can do
m=factorial(n)/(factorial(n-k)*factorial(k))
2 votes
2 thanks
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