Everything is a chemical.... Water is a chemical..... I assume you're not a chemist, Ashna?
@ Khaled Metals don't dissolve in water unless they react and then they're no longer metals...e.g. sodium. Al has an oxide film on it and does not react with water unless in the form of an amalgam where it reacts well. Mg dissolves slowly as it (slowly) reacts to form the hydroxide.
The element of Titanium (Ti) is well known to have an inherent oxide film. So, the Ti oxide film could be an excellent counter (auxiliary) electrode in a three electrodes electrochemical cell(system). Ti has high exchange current. In other words, the reversible reaction of ; Ti to Tin + ne is very fast in which the cathodic exchange current (ic) and the anodic exchange current (ia) are not only so fast but also they are equal. Therefore, the net exchange current; ic-ia=0, This implies that the Ti doesn't polarize or dissolve in water.
Everything is a chemical.... Water is a chemical..... I assume you're not a chemist, Ashna?
@ Khaled Metals don't dissolve in water unless they react and then they're no longer metals...e.g. sodium. Al has an oxide film on it and does not react with water unless in the form of an amalgam where it reacts well. Mg dissolves slowly as it (slowly) reacts to form the hydroxide.
The question wasn't clear, So If Ashna's question was " ......Ti in aqueous solution without using chemicals", meant in water, the TiO2 wouldn't dissolve in water because of the reasons that I had mentioned earlier.
According to Davilliers et al., The metal is covered by a stable oxide film of TiO2 when the metal is exposed to air or anodised. Its corrosion resistance is excellent in many media, but its corrosion rate may be significant in concentrated acid solutions. For example, the protecting oxide film is dissolved gradually in concentrated sulfuric acid.
It is not always possible to evidence the dissolution of TiO2 from usual electrochemical methods (polarisation resistance determination; impedance measurements) because that reaction is counter-balanced by the passivation of the
electrode (formation of a TiO2 layer). When the dissolution rate is greater than the formation rate in sulphuric acid, some parts of the electrode are naked. This situation is easy to detect by different techniques:
1. from the OCP curves: sharp decrease of the potential, leading to very negative values.
2. from impedance diagrams: decrease of the real part of impedance, especially in the high frequency loop.
3. from the measurement of the polarisation resistance Rp: its value is very small when the electrode is no more covered by a TiO2 layer.
Interesting, the real issue is that in order to dissolve Ti in water, it must form ions, but Ti ions spontaneously hydrolyze with water at neutral pHs to form oxides or hydroxides that precipitate from the solution. They will also form on the surface of the metal causing it to passivate, as discussed above. So, you need some way to stabilize the Ti ions in the aqueous solution. One way is to lower the pH (such as with sulfuric acid), another would be to find a chelating agent that will form complexes with the Ti ions that will not interfere with your synthesis. I would make a suggestion, but this is not my field.
One approach is through electrolysis. This method is known when it is necessary to process titanium for making a tool. It may partially enter the aqueous solution by foamy or bulk erosion.